The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » sci.math.* » sci.math

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: need algebraic identity
Replies: 1   Last Post: Oct 17, 1999 10:22 PM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Chuck Cadman

Posts: 16
Registered: 12/12/04
Re: need algebraic identity
Posted: Oct 17, 1999 10:22 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

Larry Mintz wrote in message <7ue10b$f2u$>...
>How can I factor x^n-y^m n<>m ?
>I would like it similar to the identity

b^n-a^n=(b-a)(b^(n-1)+b^(n-2)a+....+a^n-1) if it is
>Basically I trying to do the following:
>|| a_n^n -a_m^m||<=|a_n-a_m| || ? ||
>where a={a_n} is a Cauchy sequence.

I don't think it's going to work. If a_n = 2^(n^(-1/2)), then a_n converges
to 1. However, a_n^n = 2^(n^(1/2)) diverges.

Chuck Cadman

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.