Silver AlloyDate: 07/12/2001 at 00:31:55 From: Milad Subject: Problem Solving Sterling Silver is 92.5% pure silver. How many grams of pure silver and sterling silver must be mixed to obtain 100g of a 94% Silver alloy? Date: 07/12/2001 at 14:52:38 From: Doctor Greenie Subject: Re: Problem Solving Hello, Milad - Thanks for sending your question to us here at Dr. Math. I found several pages in the Dr. Math archives where similar problems are discussed by doing a search using the keyword mixture . You may want to perform that search yourself and look at some of the other explanations for similar problems provided by other math doctors. http://mathforum.org/mathgrepform.html The traditional method for solving a problem like this (used in all the examples I found in the archives) is to write an equation relating the amounts of pure silver in the two "input" mixtures and in the "output" mixture. In your problem you have one "input" mixture that is 92.5% silver and another that is 100% silver; and your "output" mixture is 94% silver. The amounts of the two input mixtures are unknown; the amount of the output mixture is 100g. Let x = grams of 92.5% silver alloy Then, since the total weight is 100g, we have (100-x) = grams of 100% silver We now write an equation relating the amounts of pure silver in the two "input" mixtures and in the "output" mixture: "x" grams at 92.5% silver + (100-x) grams at 100% = 100g at 94% (x)(0.925) + (100-x)(1.0) = (100)(0.94) 0.925x + 100 - x = 94 6 = 0.075x 6000 = 75x 6000/75 = x 80 = x So to make 100g of an alloy of 94% silver, you need to mix 80g of 92.5% alloy and 20g of pure silver. And now here is a completely different approach to the same problem. I prefer this method, because I find the calculations are usually easier. Understanding why this method works is probably a bit more difficult than understanding the traditional method, but it works for me, so I use it. Take a look at this alternative method and see if you like it. We have two "input" mixtures; one of 92.5% silver and the other of 100% silver. We want to make a mixture of 94% silver. If I think of plotting these percentages on a number line, I see that the "distance" from 92.5% to 94% is 1.5%, while the "distance" from 94% to 100% is 6%. And now here is the key to my method: The distances from 92.5% to 94% and from 94% to 100% are 1.5% and 6%; these two distances are in the ratio 1:4. This means that the two "input" mixtures must be mixed in the ratio 1:4 to get the 94% alloy. If there are to be 100g of the 94% alloy and the two input mixtures are in the ratio 1:4, then there must be 20g of one input and 80g of the other. Because the resulting alloy is closer to 92.5% than 100%, the required amounts of the inputs are 80g of the 92.5% alloy and 20g of the 100% silver. - Doctor Greenie, The Math Forum http://mathforum.org/dr.math/ |
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