Differentiating y = x^xFrom: Antill J M Date: Thu, 3 Nov 94 17:44:02 GMT Subject: Problem Please could you differentiate y=X^X that's X to the power of X From: Dr. Ken Date: Thu, 3 Nov 1994 12:58:23 -0500 (EST) Hello! In problems like these, where the variable is in an exponent, try rewriting the problem as y = e^(log(x^x)). That's x log(x ) y = e . Then you can use the properties of logarithms and the product rule to differentiate more easily. -Ken |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/