Basics of Trigonometry
Date: 12/12/2001 at 13:12:19 From: Coley Subject: Why is trig important? Why is trigonometry important? It is hard. Why is it necessary for us to know trig?
Date: 12/12/2001 at 16:18:46 From: Doctor Jeremiah Subject: Re: Why is trig important? Hi Coley, It really isn't hard. If it seems hard that's because you were taught in a manner that doesn't work for you. Different people learn different ways, but teachers sometimes only teach one way (whatever way they are best at), whereas the way you are taught needs to be the way you learn. One of the main things that needs to be taught when you learn something is what it's good for and what you need it for. If that wasn't part of what you learned, then that is probably why you don't understand it. Trigonometry is necessary any time there is an angle involved (the angle of the sun, the angle of the cue ball in a game of pool...) or any time you have to compare two non-parallel lines (the height of a building and the height of its shadow, the distance a train is from the crossing and the distance a car is from the crossing). These kinds of problems cannot easily be solved without trig. But what is trig? There are only three important definitions in trigonometry. Everything else is based on those three. If you can understand these three definitions, you should have no trouble understanding any other part of trig. First, consider a triangle with a right (90-degree) angle: Pick an angle at random (not the 90-degree angle) and label it a, as I did below. Then label the side that doesn't touch the right angle as the hypotenuse (for the origin and meaning of the word hypotenuse, see: Origin, Meaning of 'Hypotenuse' http://mathforum.org/library/drmath/view/57748.html Now one of the remaining sides is touching your angle. That is the adjacent side. And the other one? The other one is the side opposite to your angle. Now your triangle looks like this: + /| / | / | / | / | hypotenuse | / | / opposite / | / | / a | +-----------+ adjacent Now here are the three most important definitions: sine of the angle = opposite / hypotenuse cosine of the angle = adjacent / hypotenuse tangent of the angle = sine of the angle / cosine of the angle And in your case (where the angle is labelled "a") it is: sin(a) = opposite / hypotenuse cos(a) = adjacent / hypotenuse tan(a) = sin(a) / cos(a) = opposite / adjacent So, for example, say we had the very famous Pythagorean triangle with sides of 3, 4 and 5: + /| / | / | / | / | 5 / | / | / | 4 / | / | / a | +-----------+ 3 What is the value of a? Well we have all three sides so we could use any one of those equations, but if we pick one at random (the one for the tangent) tan(a) = opposite / adjacent tan(a) = 4 / 3 Now we know that the tangent of the angle "a" is 4/3 but that doesn't answer our question. We need to know the angle itself and not the tangent. Think about the square and the square root. These are opposite functions and they cancel each other out. What if we had a function that could undo the tangent function. Lets pretend it exists and call it the arctangent. Then: arctan( tan(a) ) = arctan( opposite / adjacent ) arctan( tan(a) ) = arctan( 4/3 ) Since they cancel each other arctan( tan(a) ) = a we end up with this: arctan( tan(a) ) = arctan( 4/3 ) a = arctan( 4/3 ) a = 53.1301 degrees Now we just need a button on our calculator that does the arctangent function. But wait, there is one! So we can figure out the angle when we are given the lengths of the sides. But what if we want to calculate the length of one of the sides and we know the angle. + /| / | /20| / | / | / | h / | / | / | / | / | +-----------+ 10 For example imagine this is a building. And the shadow is 10 feet long. And we know that at this time of year and at this location on the Earth the sun has an angle of 20 degrees from the perpendicular. What is the height of the building? If we wanted to find "h" (the height) we would need an equation that involved an angle and the side opposite from it (10) and the side adjacent (h). We do not want an equation that includes the hypotenuse. Well, isn't that just the equation for the tangent of an angle? tan(a) = opposite / adjacent tan(20) = 10 / h Now, using a little algebra (and using * to mean multiplication): tan(a) = opposite / adjacent tan(20) = 10 / h h * tan(20) = h * 10 / h h * tan(20) = 10 h * tan(20) / tan(20) = 10 / tan(20) h = 10 / tan(20) h = 10 / 0.3640 h = 27.4748 feet Now we just need a button on our calculator that does the arctangent function. But wait, there is one! So we can calculate any part of a right triangle if we know any other two parts. But what about a triangle that doesn't have a 90-degree angle? What can we do about that? Well, it turns out that any shape can be completely made of right triangles. Consider this triangle: + + 120 + + + + + + 45 15 + +----------------------------------+ That triangle doesn't have any right angles at all. But it's the same as these two right triangles: + + | + + | + + | + + | + +---------+------------------------+ So we could do all the algebra and figure it all out, or we could take the shortcut and use the equations that other people figure out. The most famous one is the cosine law. To use the cosine law we need to label our triangle. But we can't use hypotenuse so we can't label it the same way. So we will use letters instead: + + C + a b + + + + + A B + +----------------------------------+ c Notice that corresponding letters of the alphabet are the opposite sides to their angles. That is very important. So side c is opposite angle C. The cosine law looks like this: c^2 = a^2 + b^2 - 2ab cos(C) It looks sort of like the Pythagorean Theorem, doesn't it? Remember, you could do the algebra yourself and get this equation by breaking the triangle into two right triangles. Notice that to use the cosine law all you need is two sides and the angle between them. + + + 8 + + + + + 20 + +----------------------------------+ 10 Here is a triangle with no 90-degree angles, but we do have enough information to use the cosine law. Let's label our triangle so that c is the side that doesn't have a value: + + + b=8 c + + + + + C=20 + +----------------------------------+ a=10 c^2 = a^2 + b^2 - 2ab cos(C) c^2 = 10^2 + 8^2 - 2*10*8*cos(20) c^2 = 100 + 64 - 160*cos(20) c^2 = 164 - 160*cos(20) c^2 = 164 - 160*0.9397 c^2 = 13.6492 sqrt( c^2 ) = sqrt( 13.6492 ) sqrt = square root c = 3.6945 So now we can calculate sides of triangles that don't have 90-degree angles. And we could do angles too, but only if we have the lengths of all three sides. + + + 6 4 + + + + + + +----------------------------------+ 8 If we label this triangle so that the angle we are looking for is called C: + + C + b=6 a=4 + + + + + + +----------------------------------+ c=8 c^2 = a^2 + b^2 - 2ab cos(C) 8^2 = 4^2 + 6^2 - 2*4*6*cos(C) 64 = 16 + 36 - 48*cos(C) 64 = 52 - 48*cos(C) 64 - 52 = -48*cos(C) 12 = -48*cos(C) -12/48 = cos(C) -1/4 = cos(C) arccos( -1/4 ) = arccos( cos(C) ) arccos( -1/4 ) = C 104.4775 degrees = C And thats all there really is to trig. Most of the rest of the stuff is just algebra. Some of the algebra gets messy, but the trig really never gets more complicated than this. For more info on trig you should look at the Dr. Math FAQ: Trigonometry Formulas http://mathforum.org/dr.math/faq/formulas/faq.trig.html If you want to talk about this more or if you have a specific question, you can send it and we will try to help you figure it out. - Doctor Jeremiah, The Math Forum http://mathforum.org/dr.math/
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