Logarithm ProblemDate: 9/15/95 at 12:50:10 From: Anonymous Subject: Logarithm Help Dear Dr. Math We are students in the North River School Advanced Math class. We have finally found a problem that none of us can figure out. We were wondering if your math team could possibly help us? Here it is...... 2log(base 5) (3a+1) = log(base 5) 4 - 2log(base 5) (2a-1) ???????????????????????? HELP ???????????????????????????? Our book has an answer of 3, but we still can't figure out how they got it; the book may be wrong but we would like to know for sure. Thank you so much for your time Students Nova lotus, Kristi, Bridgit. Date: 9/15/95 at 18:53:44 From: Doctor Steve Subject: Re: Logarithm Help Hello folks, Sorry to not have time at the moment for a thorough look but it seems clear that 3 can't be right since that would give a negative number on the right side of the equation and a positive number bigger than 2 on the left. Do you see why we can say that just looking at it? It seems to us that you get the answer by solving: 6a^2 - a - 3 =0 Can you figure out where we got that equation? Write back with more questions if you have them or if you figure any mistakes we made. -- Doctor Steve, The Geometry Forum |
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