Possible Letter ArrangementsDate: 07/05/2000 at 04:42:11 From: David Stanley Subject: Permutations Is there a formula I can use to get the number of possible arrangements of five, six, or seven different letters? I can do it the long way by writing them out, but I know there must be another quicker, foolproof way. Four letters, ABCD, can be arranged in 24 different patterns. What's the trick to doing it quick? Date: 07/05/2000 at 13:14:25 From: Doctor Rick Subject: Re: Permutations Hi, David. How many choices are there for the first letter? Four, of course: it can be A, B, C, or D. Suppose you choose A. Then how many choices are there for the second letter? Only three this time; it can be B, C, or D. Suppose you choose to put B in the second position. Then how many choices are there for the third letter? There are only two choices left: the third letter can be C (with the last letter being D), or vice versa (D, then C.) Now, it doesn't matter which letter you choose to put in the second position; for each of the three choices (B, C, or D), you can make two different arrangements: Choose B --> ABCD or ABDC Choose C --> ACBD or ACDB Choose D --> ADBC or ADCB So the total number of arrangements you can make with A in the first position is 3 * 2 = 6. Go back to the first letter. There are four choices. Again, it doesn't matter which choice we make, there will be 6 arrangements we can make in each case. The total number of arrangements we can make is 4 times 6 = 24. In the time it took us to go through this, you could have written out all 24 words easily. But now you can see the rule that makes it easy to do similar problems - such as the number of arrangements for 5 letters. Look at the problem as a series of choices that you make one at a time. If the number of choices you have at one step doesn't depend on the choices you made previously, then you can just multiply the number of choices you have at each step. In your problem, you have 4 choices for the first letter, 3 choices for the second letter, and 2 choices for the third letter, so the total number of choices is 4 * 3 * 2 = 24. Does this make sense? If you're not sure, go ahead and write out all the arrangements. Organize them the way I did above, and it might help you to see why you can multiply the numbers of choices. - Doctor Rick, The Math Forum http://mathforum.org/dr.math/ |
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