Dividing Candy Among FriendsDate: 04/04/97 at 20:29:18 From: Meghan Elizabeth Clare Subject: Dividing candy Dear Dr.Math, I have 48 pieces of candy and I want to give candy to 6 friends. How many pieces of candy will each friend get? Love, Meghan Date: 05/03/97 at 19:14:03 From: Doctor Sydney Subject: Re: Dividing candy Hi Meghan, I think it is very nice of you to want to share your candy with your friends. One way to divide the candy would be to make 6 piles of candy by first putting one piece in each pile and then add one more piece to each pile and then one more piece and one more until you run out of candy. If you do this carefully you will find that each pile has 8 pieces of candy when you are done. So each friend get 8 pieces of candy. This process is called dividing, right? You are dividing 48 into 6 groups of 8 pieces. How does this relate to multiplication and division? Well, 6 times 8 = 48, right? Remember, that we can interpret 6 times 8 as meaning 6 groups of 8. So, the equation, "6 x 8 = 48" can be translated to mean "when we have 6 groups of 8 things we have a total of 48 things." We can also think about this problem in terms of division. If we want to divide 48 into 6 groups, that corresponds to figuring out what 48 divided by 6 is, right? And we know that 48 divided by 6 is 8. This agrees with our answer above! Phew! Do you see the relation between multiplication and division and your problem? How would you answer the following question: Suppose you were given 12 more pieces of candy, and suppose you still want to give an equal amount to six people. How many pieces of candy would each person get? -Doctors Judy and Sydney, The Math Forum Check out our web site! http://mathforum.org/dr.math/ |
Search the Dr. Math Library: |
[Privacy Policy] [Terms of Use]
Ask Dr. Math^{TM}
© 1994-2013 The Math Forum
http://mathforum.org/dr.math/