From: LHHK21A@prodigy.com
Here is our solution to the problem of the month:
1.) The twelve possible pentaminoes are . . .
a. _
|_|_ _ _
|_|_|_|_| (given)
b. _
|_|_
|_|_|
|_|_|
c. _
|_|
|_|_ _
|_|_|_|
d. _
|_|
_|_|_
|_|_|_|
e. _ _
|_|_|
|_|_
|_|_|
f. _ _
|_|_|_
|_|_|
|_|
g. _ _
|_|_|_|
|_|_|_|
h. _
_|_|_
|_|_|_|
|_|
i. _ _ _ _ _
|_|_|_|_|_|
j. _
_|_|_ _
|_|_|_|_|
k. _ _
|_|_|_ _
|_|_|_|
l. _ _
|_|_|_
|_|_|
|_|
2.) There are four possibe rectangles with an area of 60 and integer
sides greater than two. The sides have to be greater than two
because if they weren't not all of the pentanomoes could possibly fit
in the rectangle.
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
| _| |_ _ _ _ _| _ _| | | |_ _ _| | |
| |_ _| | |_ _|_ _| |_ |_| _ _| |
|_ _|_|_ _ _|_ _ _ _|_|_ _ _|_ _|_|_ _ _|
3 x 20
_ _ _ _ _ _ _ _ _ _ _ _
| |_ _ | _ |_ _ _| |
| _ _| |_| |_| |_| _ _|
|_| _|_|_ |_ _|_| |
| _| _ _|_ _|_| |_ _ _|
|_|_ _|_ _ _ _ _|_ _ _ _|
5 x 12
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _
| _| |_ |_ _ _ _ _|_ |_ _ |
| |_ _| _| | _| | |_ _ _| |
| | |_| |_| _| | | _ _| |_|
|_|_ _ _|_ _|_ _|_ _|_|_ _ _ _|
4 x 15
_ _ _ _ _ _ _ _ _ _
| |_ _ _ _ _|_ _ _ |
| _| |_ |_ | |_|
| |_ _|_ | |_ _ _|
|_| |_| | |_|_ _|_ |
| _ _| | _ _| _| |
|_|_ _ _|_|_ _ _|_ _|
6 x 10
Well that's it. I hope that you can understand the diagrams. I wish I could've used some different form of software but it just wasn't possible.
Thanks for your time . . .
Yours truly,
April Price
Hayley Tanler
Juli Timmony