Q-? A8! uG@@ @`uDtuI@RJubuIuIA CdCREJB CBu z\ D CB16]E CCbP C\Cn ic r e P n[&$This sketch illustrates that, for the Poincare disk, hyperbolic reflection corresponds to Euclidean inversion. Namely, assume that the blue circle (= hyperbolic line) is given and that P is a given point. Then P' is constructed as the inverse of P in the given circle. The green circle is the hyperbolic line through P and P'. One observes that the green and blue circles intersect orthogonally and that P and P' are equidistant from the blue circle (where distances are measured hyperbolically). Hence, P' is the hyperbolic reflection of P.=OhzBgBg1 CdCRC?5%F?5%F'oV@j CdCRCB?t 6 p CCbCB?'r moz CdCRC\C?=Ogy 1 CdCRCazCR0'k CBCC?#H CC, 'porta C\CCC ? HMF  C&QB U'Nq CC,C@C? TYhe oU o BiC&G m CdCRC&QB?Spene b CdCRBiC&?E'n C&PBCARR0?' umNotc BiC&CAŒh?< A\.G C@"VkpdowsVe C59   zAt r CBC@"V?jc f C\CC59 ?=#B(J CeBzb% X CH?<'s CeBzb$CB]"?>'g CH?=C!f?x}K CՊB? K2 CՊB?C?5%F?5%F'Tt CՊB?C\C?wTt x C\CCՊB??'Tu C\CC@hTp? BGQ CGCO!GLTN  C Cw'"N3 CGCOBW?5%F?5%F#$' 2v C Cw'CՊB??$!#&(R CB 8=%>CDS C9Co[%'w C Cw'Cn"Ct~?&$ "CU y CB 8=C9Co[?('P' CeC)) 16P' Cx^C *!6s, o d' Cx^C C\C?,2 h' CeC)CC?+  no W'  C/C@- UC1 CC CT.'" ande1 C0C@C{Ba@x?-/ ' l'j1 CC CTC,6Cl?.0U Y1 CsA11D1@ CPsC¨2`Yt41 CsAC\?5%F?5%F3,?51 CPsC¨C~?5%F?5%F4+ Q1 C0 5 SQ1 C$0C5qUvZA1 CcCB渲 5a~fB1 Cx.B5}]bE1 CBRC 6]bF1 BC 6V Q1 CrC" 6!11 ?!dDistance(B1 to P) = @ 1.45 inchesV< :"4Hl21 ?IDistance(A1 to P) = @ 1.77 inchesV< 95GUP31 @X/%HDistance(B1 to Q) = @ 2.08 inchesV< :8HZN 41 ?EDistance(A1 to Q) = @ 1.11 inchesV< 98[mS61 @X/%HDistance(B1 to Q) = @ 2.08 inchesV< :8n71 ?EDistance(A1 to Q) = @ 1.11 inchesV< 98t81 @FȘDistance(B1 to P') = @ 2.53 inchesV< :,'91 ?uDistance(A1 to P') = @ 0.59 inchesV< 9,!11 Distance(E1 to P) = @ 0.71 inchesV< ;"4 12 Distance(F1 to P) = @ 2.93 inchesV< <5GT13 Distance(E1 to Q) = @ 1.19 inchesV< ;=HZ"14 Distance(F1 to Q) = @ 2.49 inchesV< <=[mTl 16 Distance(F1 to Q) = @ 2.49 inchesV< <=n'17 Distance(E1 to Q) = @ 1.19 inchesV< ;=218 Distance(F1 to P') = @ 1.91 inchesV< <+19 Distance(E1 to P') = @ 1.79 inchesV< ;+BTl59  ?bR  d(P, Q) = 1 to P') = @0.83 inchesV< 64>A?@Tfo10  ?b;( d(P', Q) = to P') = @0.83 inchesV< 64BECD vT15   d(P, Q) = to P') = @0.68 inchesV< 64FIGH /t20   d(P', Q) = to P') = @0.68 inchesV< 64LKMJ