T2T || FAQ || Ask T2T || Teachers' Lounge || Browse || Search || Thanks || About T2T
View entire discussion
From: Michael Sakowski To: Teacher2Teacher Public Discussion Date: 2007091308:52:49 Subject: Polynomial Fractions The equation for resistors in parallel comes to mind. See http://www.physics.uoguelph.ca/tutorials/ohm/Q.ohm.intro.parallel.html We use the inverse of this operation (partial fraction decomposition) a lot in calculus and differential equations. For example, to find the integral of 1/(x^2 - x - 6) we would "un-add" and break up this expression into two simpler rational expressions using partial fraction decomposition. We would get the integral of [(1/5)/(x-3) + (-1/5)/(x+2)] which could then easily be integrated. In order to check the decomposition of the above result (or even understand the process), one must know how to add rational expressions.
Math Forum Home || The Math Library || Quick Reference || Math Forum Search