To: Teacher2Teacher Public Discussion
Subject: Re: Re:find formula for equation and answer
On 2005061602:01:04, John wrote: > >Turn the two fractions into one fraction and set numerator and >denominator equal to each other. Solve the system. > >Like this Given: 1/a +1/b = 37/180 > >Multiply 1/a by "b" and 1/b by "a" yielding > > (a+b)/ ab =37/180 > >Set numerator and denominators equal to each other: > > a+b = 37 and ab = 180 so, >a=180/b > >Substitute into other equation: b + (180/b) = 37 >Multiplying by b and bringing everything to left >b^2 -37b + 180 = 0 >Using quadratic formula: b= (37 + sqr(649))/2 and > a= 37-((37 + sqr(649))/2 > >The quad. almost factors so I wonder if there is an error in the >fraction 37/180 > What I would like to know is how did you get b^2 and is "sqr" a symbol for square root of 649 or is it 649 squared? What is the final answer to this equation? Are "a" and "b" even whole numbers, or are we dealing with decimals here?
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